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B
14b√b−a
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C
34a√a+b
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D
35b√b−a
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Solution
The correct option is B14b√b−a We have, limx→b√x−a−√b−ax2−b2 =limx→b(√x−a−√b−a)(√x−a+√b−a)(x−b)(x+b)(√x−a+√b−a) =limx→bx−b(x−b)(x+b)(√x−a+√b−a) =limx→b1(b+b)(√x−a+√b−a) =12b(2√b−a)=14b√b−a