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Question

The value of logab−log|b| is equal to

A
loga
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B
log|a|
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C
loga
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D
none of these
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Solution

The correct option is A log|a|
Let k=logablog|b|
Case 1:
If b>0, then |b|=b
k=logablog|b|
k=loga+logblogb
k=loga
Case 2:
If b<0, then |b|=b
k=logablog(b)
k=log(abb)
k=log(a)
From case 1 & case 2:
k=log|a|
Ans: B

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