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B
log|a|
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C
−loga
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D
none of these
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Solution
The correct option is Alog|a| Let k=logab−log|b| Case 1: If b>0, then |b|=b k=logab−log|b| ⇒k=loga+logb−logb ⇒k=loga Case 2: If b<0, then |b|=−b k=logab−log(−b) ⇒k=log(ab−b) ⇒k=log(−a) From case 1 & case 2: k=log|a| Ans: B