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Question

The value of sin1cotsin1 (234)+cos1124+sec12 is

A
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Solution

The correct option is A 0
We have sin1cotsin1 (234)+cos1124+sec12
=sin1[cot(sin1(3122)+cos132+cos112)]
=sin1[cot(150+300+450)]=sin1[cot900]=sin10=0

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