Question

The value of $E_{reduction}$ of a hydrogen electrode at $pH=0$ and $298K$, $1atm$ is:

• A. $0.59V$
• B. $0V$
• C. $-0.59V$
• D. $-0.059V$

Answer 1

The correct option is B $0V$

We know,$E_{red}=E_{cell}^{\circ }-\frac{0.0591}{1}log\frac{1}{\left[H^{+}\right]}$
The reduction reaction here is
$H^{+}+e^{-}⟶\frac{1}{2}{H}_2\left(g\right)$
Given,
$pH=0\Rightarrow -log\left[H^{+}\right]=0\Rightarrow \left[H^{+}\right]=1M$
$\therefore E_{red}=0-\frac{0.0591}{1}log1=0V$