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Escape Velocity

The value of ...

Question

The value of escape velocity on earth is:

11.2 k m s^{- 1}

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11.2 k m s^{- 2}

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10.2 m s^{- 1}

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11.2 m s^{- 2}

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Solution

The correct option is A $11.2 k m s^{- 1}$
Escape velocity is the minimum speed needed for an object to escape from the gravitational influence earth.
For escape velocity
$K E + U = 0$
$\frac{1}{2} m v^{2} = \frac{G M m}{r}$
$v_{e s c a p e} = \sqrt{\frac{2 G M}{r}}$
$V_{e s c a p e} = 11.2 K m S^{- 1}$

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