The value of i in the following circuit diagram will be

\frac{3}{2} A

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\frac{3}{4} A

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\frac{1}{2} A

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1 A

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Solution

The correct option is D $1 A$
Using Kirchhoffs's loop rule we get

$8 - 4 i - 4 i = 0$

Thus we get $i = 1 A$

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Similar questions

x = 2 a - 1

y = (2 a - 2)

z = 3 - 4 a

x^{3} + y^{3} + z^{3}

Area of the triangle formed by the points $((a + 3) (a + 4) a + 3), ((a + 2) (a + 3), (a + 2))$ and $((a + 1) (a + 2) (a + 1))$

∣ ∣ ∣ ∣ ∣ \begin{matrix} (a + 1) (a + 2) & a + 2 & 1 (a + 2) (a + 3) & a + 3 & 1 (a + 3) (a + 4) & a + 4 & 1 \end{matrix} ∣ ∣ ∣ ∣ ∣

|\begin{matrix} (a + 1) (a + 2) & a + 2 & 1 \\ (a + 2) (a + 3) & a + 3 & 1 \\ (a + 3) (a + 4) & a + 4 & 1 \end{matrix}| = - 2

2 a + 3 = 6

\frac{3}{4 a + 6}

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