Question

The value of $K_c$ for the reaction $A+B\leftrightharpoons C+D$ was found to be $0.0997$ at a certain temperature. If the initial concentrations of $A$ and $B$ are both $1M$. What are the equilibrium concentrations of $A,B,C$ and $D$?

Answer 1

$A+B\rightleftharpoons C+D$

$1-x$ $1-x$ $x$ $x$

$K_c=\frac{x^2}{(1-x{)}^2}=0.0997\Rightarrow \frac{x}{1-x}=0.316$

$\therefore x=0.24$

$\therefore \left[C\right]=\left[D\right]=0.24$

$\left[A\right]=\left[B\right]=1-0.24=0.76$