The value of k for which the lines kx+y=6 and 2x−5y=1 are perpendicular to each other is
−52
25
+52
−25
kx+y=6
y=−kx+6
5y=2x−1
y=25x−1
So, (−k)×(25)=−1
k=52
Find the value of k for which the lines kx - 5y + 4 = 0 and 5x - 2y + 5 = 0 are perpendicular to each other
Find the value of k for which the lines k – 5y + 4 = 0 and 2 – y + 15 = 0 are ⊥ to each other.
If the lines given by 3x+2y=2 and 2x+5y+1=0 are parallel then the value of k is
(a) −54 (b) 25 (c) 32 (d) 154