The value of $k$ if $(4, k)$ passes through $x + 3 y = 0$

- \frac{4}{3}

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\frac{4}{3}

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\frac{1}{3}

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\frac{- 1}{3}

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Solution

The correct option is A $- \frac{4}{3}$
$x + 3 y = 0 (4, k) 4 + 3 k = 0 3 k = - 4 k = - \frac{4}{3}$

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Similar questions

Find the value of k, if 2x + 3y = 13 passes through the point (2k,3k)

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\pm \frac{2}{3}

\pm \frac{1}{3}

\pm \frac{3}{4}

\pm \frac{4}{3}

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\frac{(3 x - 4)^{3} - (x + 1)^{3}}{(3 x - 4)^{3} + (x + 1)^{3}} = \frac{61}{189}

\frac{- 5}{4}

\frac{5}{4}

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\frac{4}{3}

\frac{{(3 x - 4)}^{3} - {(x + 1)}^{3}}{{(3 x - 4)}^{3} + {(x + 1)}^{3}} = \frac{61}{189}

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