CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The value of λ for which the set {(x,y):x2+y26x+4y12}{(x,y):4x+3yλ} contains only one point is 
  1. 19 
  2. 31
  3. 31
  4. 19


Solution

The correct option is D 19
x2+y26x+4y12=0
Centre of the circle is (3,2) and radius is 9+4+12=5
Clearly, 4x+3y=λ should be tangent to the circle x2+y26x+4y12=0.
∣ ∣4(3)+3(2)λ42+32∣ ∣=5
λ=31 (or) λ=19

Now, for only one point of intersection,
4x+3yλ must not satisfy the centre of the circle.
λ=19 

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image