The value of a-b- - c-d- - b-c- - a-d- - c-a- - b-d- is

The correct option is B 0 ( a⃗×b⃗ ). ( c⃗×d⃗ )+ ( b⃗×c⃗ ). (a⃗×d⃗ )+ (c⃗×a⃗ ). (b⃗×d⃗ #160; ) [ (a⃗×b⃗×c⃗ #160; )+ ( b⃗×c⃗×a⃗ )+ (c⃗×a⃗×b⃗ #16 ...

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Proof by mathematical induction

The value of ...

Question

The value of $(\to a \times \to b) . (\to c \times \to d) + (\to b \times \to c) . (\to a \times \to d) + (\to c \times \to a) . (\to b \times \to d)$ is

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none of these

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(\to b \times \to c) . (\to a \times \to d) + (\to c \times \to a) . (\to b \times \to d)

+ (\to a \times \to b) . (\to c \times \to d) =

\to a \times \to b = \to c \times \to d

\to a \times \to c = \to b \times \to d

\to a - \to d, \to b - \to c

[\to b \to c \to d] = 4

(\to a \times \to b) \times (\to c \times \to d) + (\to a \times \to c) \times (\to d \times \to b) + (\to a \times \to d) \times (\to b \times \to c) + k \to a = 0

k

\to a, \to b, \to c, \to d

(\to a \times \to b) \times (\to c \times \to d) + (\to a \times \to c) \times (\to d \times \to b) + (\to a \times \to d) \times (\to b \times \to c)

\to b, \to c, \to d

(\to a \times \to b) \times (\to c \times \to d) + (\to a \times \to c) \times (\to d \times \to b) + (\to a \times \to d) \times (\to b \times \to c)

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