The value of lim x - 1-sinsin -1 x- isA- does not existB- - - 2C- 0D- 1

The correct option is D 1 lim_x→ 1^ [sin sin^ 1x]=lim_x→ 1[sin sin^ 1x]=1 (Hence x→1 means x→1 , ∵ sin sin 1 x is not defined for x gt;1 ) Hence (a) is th ...

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Standard XI

Mathematics

Algebra of Derivatives

The value of ...

Question

The value of $lim x \to 1^{-} [s i n s i n^{- 1} x]$ is

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does not exist

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π/2

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Solution

The correct option is A
1

$lim x \to 1^{-} [s i n s i n^{- 1} x] = lim x \to 1 [s i n s i n^{- 1} x] = 1$

(Hence x→1 means x→1^-, ∵ sin sin^-1x is not defined for x>1 )

Hence (a) is the correct answer

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Q. If

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The value of limx→1−[sin sin−1x] is

The correct option is A 1 limx→1−[sin sin−1x]=limx→1[sin sin−1x]=1 (Hence x→1 means x→1-, ∵ sin sin-1 x is not defined for x>1 ) Hence (a) is the correct answer

The value of $lim x \to 1^{-} [s i n s i n^{- 1} x]$ is

The correct option is A
1

$lim x \to 1^{-} [s i n s i n^{- 1} x] = lim x \to 1 [s i n s i n^{- 1} x] = 1$

(Hence x→1 means x→1^-, ∵ sin sin^-1x is not defined for x>1 )

Hence (a) is the correct answer