wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of limx0 1+x21x2x is

Open in App
Solution

limx0 1+x2 1x2x=limx0 1+x2 1x2x×1+x2 + 1x21+x2 + 1x2=limx0 (1+x2)2 (1x2)2x(1+x2 + 1x2)=limx0 (1+x2) (1x2)x(1+x2 + 1x2)=limx0 1+x21+x2x(1+x2 + 1x2)=limx0 2x2x(1+x2 + 1x2)=limx0 2x1+x2 + 1x2=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
3 Sides and 2 Included Angles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon