The value of ${log}_{3} 9 + {log}_{5} 25 + {log}_{2} 8$ is

4

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5

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6

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7

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Solution

The correct option is D $7$
${log}_{3} 9 + {log}_{5} 25 + {log}_{2} 8 = {log}_{3} {(3)}^{2} + {log}_{5} {(5)}^{2} + {log}_{2} {(2)}^{3} = 2 {log}_{3} {(3)} + 2 {log}_{5} {(5)} + 3 {log}_{2} {(2)} = 7$

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Similar questions

Q. Prove that

{log}_{3} 2 \times {log}_{4} 3 \times {log}_{5} 4 \times {log}_{6} 5 \times {log}_{7} 6 \times {log}_{8} 7 = \frac{1}{3}

f (x) = {log}_{7} {log}_{5} {log}_{3} {log}_{2} ({2 x}^{3} + {5 x}^{2} - 14 x)

Q. Solve the equation in each of the following.
(i)

{log}_{4} (x + 4) + {log}_{4} 8 = 2

(ii)

{log}_{6} (x + 4) - {log}_{6} (x - 1) = 1

(iii)

{log}_{2} x + {log}_{4} x + {log}_{8} x = \frac{11}{6}

(iv)

{log}_{4} (8 {log}_{2} x) = 2

(v)

{log}_{10} 5 + {log}_{10} (5 x + 1) = {log}_{10} (x + 5) + 1

(vi)

4 {log}_{2} x - {log}_{2} 5 = {log}_{2} 125

(vii)

{log}_{3} 25 + {log}_{3} x = 3 {log}_{3} 5

(viii)

{log}_{3} (\sqrt{5 x - 2}) - \frac{1}{2} = {log}_{3} (\sqrt{x + 4})

Find the values of the following:
(i) |11 $-$ 25|

(ii) |9| + | $-$ 9|

(iii) |6×3 + ( $-$ 6)×3|

(iv) |x+5 $-$ (7+x)|

(v) |4| × | $-$ 8|

(vi) | 3(3 $-$ 8) + ( $-$ 5)|

Q. The value of

l o g_{3} 4 l o g_{4} 5 l o g_{5} 6 l o g_{6} 7 l o g_{7} 8 l o g_{8} 9

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The value of log39+log525+log28 is

The correct option is D 7log39+log525+log28=log3(3)2+log5(5)2+log2(2)3=2log3(3)+2log5(5)+3log2(2)=7

The value of ${log}_{3} 9 + {log}_{5} 25 + {log}_{2} 8$ is

The correct option is D $7$
${log}_{3} 9 + {log}_{5} 25 + {log}_{2} 8 = {log}_{3} {(3)}^{2} + {log}_{5} {(5)}^{2} + {log}_{2} {(2)}^{3} = 2 {log}_{3} {(3)} + 2 {log}_{5} {(5)} + 3 {log}_{2} {(2)} = 7$