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Byju's Answer
Standard IX
Mathematics
Property 2
The value of ...
Question
The value of
log
a
b
−
log
|
b
|
=
A
log
a
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B
log
|
a
|
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C
−
log
a
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D
None of these
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Solution
The correct option is
B
log
|
a
|
log
a
b
is defined if ab > 0 or a and b have the same sign.
Case (i): a, b > 0:
⇒
log
a
b
−
log
|
b
|
=
log
a
+
log
b
−
log
b
=
log
a
...(i)
Case (ii): a, b < 0:
⇒
log
a
b
−
log
|
b
|
=
log
(
−
a
)
+
log
(
−
b
)
−
log
(
−
b
)
=
log
(
−
a
)
...(ii)
From Eqs. (i) and (ii), we have
log
a
b
−
log
|
b
|
=
l
o
g
|
a
|
.
Suggest Corrections
0
Similar questions
Q.
Find the value of log a + log b - log ab.
___
Q.
Solve the system of equations:
l
o
g
a
x
l
o
g
a
(
x
y
z
)
=
48
l
o
g
a
y
l
o
g
a
(
x
y
z
)
=
12
,
a
>
0
,
a
≠
1
l
o
g
a
z
l
o
g
a
(
x
y
z
)
=
84
Q.
If
a
1
,
a
2
,
a
3
⋯
,
a
n
,
⋯
are in G.P., then the determinant
Δ
=
∣
∣ ∣
∣
l
o
g
a
n
l
o
g
a
n
+
1
l
o
g
a
n
+
2
l
o
g
a
n
+
3
l
o
g
a
n
+
4
l
o
g
a
n
+
5
l
o
g
a
n
+
6
l
o
g
a
n
+
7
l
o
g
a
n
+
8
∣
∣ ∣
∣
is equal to
Q.
If
a
1
,
a
2
,
a
3
⋯
,
a
n
,
⋯
are in G.P., then the determinant
Δ
=
∣
∣ ∣
∣
l
o
g
a
n
l
o
g
a
n
+
1
l
o
g
a
n
+
2
l
o
g
a
n
+
3
l
o
g
a
n
+
4
l
o
g
a
n
+
5
l
o
g
a
n
+
6
l
o
g
a
n
+
7
l
o
g
a
n
+
8
∣
∣ ∣
∣
is equal to
Q.
Show that:
2
(
√
l
o
g
a
4
√
a
b
+
l
o
g
b
4
√
a
b
−
√
l
o
g
a
4
√
b
/
a
+
l
o
g
b
4
√
a
/
b
)
.
√
l
o
g
a
b
=
{
2
,
b
≥
a
≥
1
2
l
o
g
a
b
,
1
<
b
<
a
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