The value of $l o g_{b} a . l o g_{c} b . l o g_{a}$ c is

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log abc

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Solution

The correct option is C 1
$l o g_{b} a . l o g_{c} b . l o g_{a} c$
$\frac{l o g a}{l o g b} . \frac{l o g b}{l o g c} . \frac{l o g c}{l o g a}$
= 1

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