Question

The value of m for which ${\left[{\left\{{\left(\frac{1}{7^2}\right)}^{-2}\right\}}^{-1/3}\right]}^{1/4}=7^m,$ is

(a) $-\frac{1}{3}$

(b) $\frac{1}{4}$

(c) −3

(d) 2

Answer 1

We have to find the value of for

By using rational exponents

$7^{\frac{-1}{3}}=7^m$

Equating power of exponents we get

Hence the correct choice is .