wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of m(k=ma2) for which the given value is a solution of the given equation :
x2+3ax+k=0,x=a is

Open in App
Solution

x2+3ax+k=0
Substituting x=a,
(a)2+3a(a)+k=0
a23a2+k=0
2a2+k=0
k=2a2
Now substituting k=ma2
ma2=2a2
m=2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Higher Order Derivatives
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon