Question

The value of magnetic field between plates of capacitor, at distance of $1m$ from centre where electric field varies by ${10}^{3}V/m/s$ will be:

• A. $5.56T$
• B. $5.56\mu T$
• C. $5.56mT$
• D. $55.6nT$

Answer 1

Answer: (D)

$55.6nT$

GIven $\frac{dE}{dt}={10}^{3}V{m}^{-1}{s}^{-1}$

$Current\left(I\right)=\frac{dQ}{dt}=\frac{dE}{dt}{ϵ}_o$

$Magnetic$ $Field=\frac{{\mu }_0}{4\pi }\frac{I}{r^2}$

By solving above both equations we get $magnetic$ $field$$=55.6nT$