The value of `n' for which the number of diagonals that can be drawn in a
polygon exceeds the number of side by 1 is -

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None of these

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Solution

The correct option is D
None of these

$\frac{n (n - 3)}{2}$ = n+1

Solving, we get `n' which is not an integer.

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The value of `n' for which the number of diagonals that can be drawn in a polygon exceeds the number of side by 1 is -

The correct option is D None of these n(n−3)2= n+1 Solving, we get `n' which is not an integer.

The value of `n' for which the number of diagonals that can be drawn in a
polygon exceeds the number of side by 1 is -

The correct option is D
None of these

$\frac{n (n - 3)}{2}$ = n+1

Solving, we get `n' which is not an integer.