The value of $n$ in the molecular formula $B e_{n} A l_{2} S i_{6} O_{18}$ is:

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Solution

$S i_{6} O_{18}^{- 12}$ is a cyclic silicate. The value of $n$ will be $3$ to balance the charge $B e_{n} A l_{2} S i_{6} O_{18} 2 n + 6 - 12 = 0 n = 3$

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