The value of -n- in the reaction -Cr 2 O 72-14 H - nFe 2-2 Cr 3- nFe 3-7 H 2 Owill be-a- 2b- 3C- 6d- 7

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Catalytic Hydrogenation

The value of ...

Question

The value of 'n' in the reaction :

Cr₂O₇^2- + 14H⁺+ nFe²⁺ --------> 2Cr³⁺+ nFe³⁺ + 7H₂O
will be,

a.) 2
b.) 3
c.) 6
d.) 7

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C r_{2} O_{7}^{2 -} + 14 H^{+} + n e^{-} \to 2 C r^{3 +} + 7 H_{2} O

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