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Question

The value of 'n' in the reaction :

Cr​​​​​​2​​​​O​​​7​​2- + 14H+ + nFe2+ --------> 2Cr3+ + nFe​​​​3+ + 7H2O
will be,

a.) 2
b.) 3
c.) 6
d.) 7

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Solution

simply balance the charge on both sides i.e. LHS = +14 - 2 + 2n RHS = 3n + 6 so LHS = RHS 12 + 2n = 3n + 6 n = 6

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