Question

The value of 'n' of the highest excited state that an electron of hydrogen atom in the ground state can reach, when $12.09eV$ energy is given to the hydrogen atom is.

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is C 3

For hydrogen atom, the energy of ground state = -13.6 eV. According to the given data 'n' be the highest excited state that an electron of hydrogen atom in the ground state can reach, when 12.09 eV energy is provided to H-atom.
Hence $E_n=-13.6+12.09=-1.51eV$
Also we know
$E_n=\frac{E_1}{n^2}$
$\therefore n^2=\frac{-13.6}{-1.51}$
$n^2=9$
$\Rightarrow n=3$