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Question

The value of numerical aperature of the objective lens of a microscope is 1.25. If light of wavelength 5000˚A is used, the minimum separation between two points, to be seen as distinct, will be :

A
0.24μm
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B
0.48μm
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C
0.12μm
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D
0.38μm
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Solution

The correct option is A 0.24μm
Numerical aperature of the microscope is given as
NA=.0.61λd
Where d= minimum sparation between two points to be seen as distinct
d=0.61λNA=(0.61)×(5000x10m10)1.25
=2.4×107m
=0.24μm

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