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Question

The value of PV for 5.6 L of an ideal gas is 0.5RT at STP.If true enter 1 else 0.
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Solution

The correct option is A 0
1 mole of an ideal gas at STP occupy a volume of 22.4 L.
Hence, 5.6 L of ideal gas at STP corresponds to the number of moles 5.6L22.4L/mol=0.5mol
PV=nRT=0.25RT
The value of PV for 5.6 L of an ideal gas is 0.25RT at STP.

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