The value of PV for 5.6 L of an ideal gas is 0.5RT at STP.If true enter 1 else 0.
0
Open in App
Solution
The correct option is A 0 1 mole of an ideal gas at STP occupy a volume of 22.4 L. Hence, 5.6 L of ideal gas at STP corresponds to the number of moles 5.6L22.4L/mol=0.5mol PV=nRT=0.25RT The value of PV for 5.6 L of an ideal gas is 0.25RT at STP.