Question

The value of $pV$ for 5.6 $L$ of an ideal gas is ..... $RT$, at $NTP$.(If your answer is $x$, then write $x\times$100)

Answer 1

At $NTP$, 1 mole of an ideal gas occupies a volume of 22.4 $L$.

Hence, 5.6 $L$ corresponds to $\frac{5.6}{22.4}=\frac{1}{4}mole$.

The ideal gas equation is $PV=nRT$

Thus, the value of $pV$ for 5.6 $L$ of an ideal gas is 0.25 $RT$, at $NTP$.