Question

The value of $PV$ for 5.6 litre of an ideal gas is $\frac{1}{x}RT$ at $STP$.

Value of $x$ is______.

Answer 1

At STP,

1 mole of a gas = 22.4 litre

No of moles$=\frac{5.6}{22.4}$

$PV=nRT$

So, $PV=\frac{1}{4}RT$

So, value of $x$ is 4.