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Question

The value of sin1[cos{cos1(cosx)+sin1(sinx)}], where x(π2,π) is equal to

A
π2
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B
π
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C
π
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D
π2
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Solution

The correct option is D π2
The value of sin1[cos{cos1(cosx)+sin1(sinx)}]
=sin1[cos{x+πx}]
=sin1[cos(π)]=sin1(1)
=π2

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