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Question

The value of sin2π8+sin23π8+sin25π8+sin27π8 is equal to

A
18
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B
14
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C
12
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D
1
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E
2
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Solution

The correct option is E 2
sin2π8+sin23π8+sin25π8+sin27π8
=2(sin2π8+sin23π8)
=2[sin2π8+cos2π8]=2×1=2

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