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Question

The value of (sin2θ+cosec2θ) is always

A
Less than 1
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B
Equal to 1
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C
Greater than or equal to 2
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D
Greater than 1 but less than 2
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Solution

The correct option is C Greater than or equal to 2
(sin2θ+cosec2θ)=sin2θ+1sin2θ
=[sin4θ+1sin2θ]
sinθ is always lies between 0 ξ 1 for all possible values of 0.
Value of (sin2θ+cosec2θ) greater than equal to 2.
Hence, the answer is greater than equal to 2.

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