Question

The value of $\sin ({60}^{\circ }+\theta )-cos({30}^{\circ }-\theta )$ is equal to

• A. $2\cos \theta$
• B. $2\sin \theta$
• C. $0$
• D. $1$

Answer 1

Answer: (C)

$0$

$\sin (60°-\theta )-\cos (30°-\theta )$

$=\cos (90°-60°-\theta )-\cos (30°-\theta )$

$=\cos (30°-\theta )-\cos (30°-\theta )$

$=0$

Hence, the answer is $0.$