The value of tan5∘tan10∘tan15∘⋯tan85∘ is
Using,
tanx=cot(90∘−x) and tanx.cotx=1
We get ,
tan5.tan10.tan15...tan80.tan85=tan5.tan10.tan15...tan45.cot(90−35)...cot(90−10).cot(90−5)=tan5.cot5.tan10.cot10...tan45=1
tan10∘tan15∘tan75∘tan80∘=?(a) 3(b) 13(c) −1(d) 1