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B
0
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C
∞
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D
12
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Solution
The correct option is A1 tan1∘tan2∘⋯tan88∘tan89∘ =tan1∘tan2∘⋯tan45∘⋯tan(90−2)∘tan(90−1)∘ =tan1∘tan2∘⋯tan45∘⋯cot2∘cot1∘ =(tan1∘cot1∘)(tan2∘cot2∘)⋯tan45∘ =1×1×⋯×1=1