The value of - in -3 tan 2 -3-0 is

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The value of θ in √3tan2θ - 3 = 0 is

45^o

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60^o

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90^o

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30^o

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Find the value of $θ$ in each of the following

(1) 2 sin 2 $θ$ = $\sqrt{3}$

(2) 2 cos 3 $θ$ = 1

(3) $\sqrt{3}$ tan 2 $θ$ - 3 = 0

If 3 \tan^{2} θ - 4 \sqrt{3} \tan θ + 3 = 0, find the acute angle s θ

If $\sqrt{3}$ tan $2 θ$ - 3 = 0 then $θ$ = ?

(a) $15^{o}$ (b) $30^{o}$ (c) $45^{o}$ (d) $60^{o}$

0^{o} < θ < 90^{o}

\sqrt{3} tan 2 θ - 3 = 0

\sqrt{3}

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