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Byju's Answer
Standard XIII
Mathematics
Properties of Determinants
The value of ...
Question
The value of the determinant
∣
∣ ∣
∣
1
a
b
+
c
1
b
c
+
a
1
c
a
+
b
∣
∣ ∣
∣
is
A
a+b+c
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B
(
a
+
b
+
c
)
2
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C
\N
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D
1+a+b+c
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Solution
The correct option is
C
\N
Δ
=
∣
∣ ∣
∣
1
a
b
+
c
1
b
c
+
a
1
c
a
+
b
∣
∣ ∣
∣
=
(
a
+
b
+
c
)
∣
∣ ∣
∣
1
1
b
+
c
1
1
c
+
a
1
1
a
+
b
∣
∣ ∣
∣
(
C
2
→
C
2
+
C
3
)
=
0
,
(
∵
C
1
≡
C
2
)
.
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