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Question

The value of the expression C1C0+2C2C1+3C3C2++nCnCn1 is

A
(n+1)(n+2)2
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B
n(n+1)2
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C
n(n1)2
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D
n(n+2)2
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Solution

The correct option is A n(n+1)2
Given:
C1C0+2C2C1+3C3C2++nCnCn1

rth term of the above expression is
Tr=rCrCr1=rnr+1r=nr+1

Now,
nr=1Tr=nr=1(nr+1)

=n2n(n+1)2+n

=n(n+1)2

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