The correct option is A 1
tan1°×tan2°×...tan89°
⇒tan1°×tan89°×tan2°×tan88°×...×tan44°×tan46°×tan45°
We know that tan(90°−θ)=cotθ.
Therefore,
tan1°=tan(90°−89°)=cot89°
tan2°=tan(90°−88°)=cot88°
⋯
Similarly, tan44°=cot46°
Now, we can write the given expression as,
cot89°×tan89°×cot88°×tan88°×...×cot46°×tan46°×tan45°
Also tanθ×cotθ=1
So we get,
tan1°×tan2°×...tan89°=1