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Question

The value of the integral 313+x3dx lies in the interval

A
(1,3)
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B
(2,30)
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C
(4,230)
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D
none of these
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Solution

The correct option is C (4,230)
As f(x)=3+x3 is monotonically increasing xϵ[1,3]
For
1<x<33+13<3+x3<3+332<3+x3<30312dx313+x3dx3130dx2[x]31313+x3dx30[x]314313+x3dx230

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