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Question

The value of the integral dxxx2a2 is equal to

A
c1asin1a|x|
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B
c1acos1a|x|
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C
sin1a|x|+c
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D
c+1asin1a|x|
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Solution

The correct option is D c1asin1a|x|
Let I=dxxx2a2
Let x=1t
dx=1t2dt
I=dtt2.1t(1t2)2a2
=1adt(1a)2t2=1asin1t+c
=1asin1a|x|+c=c1asin1a|x|

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