You visited us 1 times! Enjoying our articles? Unlock Full Access!

Elementary and Complex Reactions

the value of ...

Question

the value of the kc for the reaction 2hi gives h2 +i2 is 110^-4. at a given time the composition of reaction mixture is [hi] = 210^-5 mol , h2 = 110^-5mol i2 = 110^-5mol in which direction the reaction will proceed??

Open in App

Solution

Dear student

2HI <==> H₂ + I₂ Kc = 110^-4

After time t, [HI] = 210^-5mol, $H_{2}$ = 110^-5 mol, [I₂] = 110^-5 mol.
So after time t, Kc = $\frac{[H_{2}] [I_{2}]}{{[H I]}^{2}}$
Kc = ( 110^-5) ( 110^-5) / ( 2*10^-5)²
Kc = 0.25

The value of the equilibrium constant is increases, so the reaction will shift in the backward direction to achieve the equilibrium state.

Regards

Suggest Corrections

Similar questions

K_{c}

2 H I (g) ⇌ H_{2} (g) + I_{2} (g)

1 \times 10^{- 4}

[H I] = 2 \times 10^{- 5}

[I_{2}] = 1 \times 10^{- 5}

k_{c}

2 A ⇌ B + C

2 \times 10^{- 3}

[A] = [B] = [C] = 3 \times 10^{- 4} M

k_{c}

2 A ⇌ B + C

10^{- 3}

10^{- 4}

K_{c}

2 A ⇌ B + C

2 \times 10^{- 3}

[A] = [B] = [C] = 3 \times 10^{- 4} M

H I ⇌ 1 / 2 H_{2} + 1 / 2 I_{2}

K_{c}

K_{c}

H_{2} + I_{2} ⇌ 2 H I

Join BYJU'S Learning Program