Question

The value of Van't Hoff factor for aqueous KCL sol is close to 2, while the value of 'i' for ethanoic acid in benzene is nearly 0.5. Give reason?

Answer 1

Because vant hoff factor=final moles/initial moles
kcl->k+ +cl-
initial moles =1
final moles=2
so vant hoff factor=2/1=2
now ethanoic acid in benzene dimerises means 2 molecules become 1
hence initial moles=2 and final moles=1
vant hoff factor=1/2=0.5
I think this helps

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