What will be the value of Van't Hoff factor for ethanoic acid in benzene?

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Solution

In benzene, two molecules of ethanoic acid associate to form a dimer.
$2 C H_{3} C O O H ⇌ (C H_{3} C O O H)_{2}$
The van't Hoff factor $i = \frac{number of solute particles in solution}{theoretical number of solute particles for no association}$
$i = \frac{1}{2} = 0.5$

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The value of Van't Hoff factor for aqueous KCL sol is close to 2, while the value of 'i' for ethanoic acid in benzene is nearly 0.5. Give reason?

C H_{3} C O O H

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