The correct option is A 210^∘ Since sum of linear pair angles is 180^∘ ∴ 90^∘ + x = 180^∘ ⇒ x = 180^∘ 90^∘ = 90^∘ And z + 30^∘ = 180^∘ ⇒ z = 180^∘ ...

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Byju's Answer

Standard VIII

Mathematics

Sum of Exterior Angles of a Triangle

Question

The value of x+y is

$180^{\circ}$

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$360^{\circ}$

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$270^{\circ}$

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$210^{\circ}$

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Solution

The correct option is D
$210^{\circ}$

$S i n c e s u m o f l i n e a r p a i r a n g l e s i s 180^{\circ}$
$∴ 90^{\circ} + x = 180^{\circ} \Rightarrow x = 180^{\circ} - 90^{\circ} = 90^{\circ} A n d z + 30^{\circ} = 180^{\circ} \Rightarrow z = 180^{\circ} - 30^{\circ} = 150^{\circ} A l s o y = 90^{\circ} + 30^{\circ} = 120^{\circ}$ $E x t e r i o r a n g l e p r o p e r t y$

$∴ x + y = 90^{\circ} + 120^{\circ} = 210^{\circ}$

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The value of x+y is

The correct option is D 210∘ Since sum of linear pair angles is 180∘ ∴90∘+x=180∘⇒x=180∘−90∘=90∘And z+30∘=180∘⇒z=180∘−30∘=150∘Also y=90∘+30∘=120∘ Exterior angle property ∴x+y=90∘+120∘=210∘