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Question

The value of Z such that no current flows in branch Y will be


A
(3.46+j2)Ω
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B
(13.85+j8)Ω
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C
(6.93+j4)Ω
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D
(27.7+j16)Ω
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Solution

The correct option is C (6.93+j4)Ω


Let, VRY=V0V
VYB=V120V
VBR=V120
Let current through capacitor be IC
IC=V120Xc=V120j8
IC=V8120+90
IC=V830A
Let current though phase Y be IY
IY=ICIL
as IY=0
IC=IL
V830=V0R+jXR+jX=830=830 ΩZ=(6.93+j4) Ω

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