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Question

The values of E of some of the reactions are given below:
I2+2e2I;E=+0.54 volt
Cl2+2e2Cl;E=+1.36 volt
Fe2++eFe2+;E=+0.76 volt
Ce4++eCe3+;E=+1.60 volt
Sn4++2eSn2+;E=+0.15 volt
On the basis of the above data, answer the following questions:
(a) Whether Fe3+ oxidises Ce3+ or not?
(b) Whether I2 displaces chlorine from KCl?
(c) Whether the reaction between FeCl3 and SnCl2 occurs or not?

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Solution

(a) Chemical reaction,
Fe3++Ce3+Ce4++Fe2+
Two half reactions,
Fe3++eFe2+;Reduction;E=0.76 volt
Ce3+Ce4++e;Oxidation;EOX=1.60 volt––––––––––––––––––––––––––––––
Adding;emf=0.84 volt
Since, emf is negative, the reaction does not occur, i.e., Fe3+ does not oxidise Ce3+.
(b) Chemical reaction,
I2+2KCl=2KI=Cl2
Half reactions,
I2+2e2I;Reduction;E=0.53 volt
2ClCl2+2e;underlineOxidation;EOX=1.36 volt
Adding;emf=0.82 volt
Since, emf is negative, the reaction does not occur, i.e., I2 does not displace Cl2 from KCl.
(c) Chemical reaction,
SnCl2+2FeCl3SnCl4+2FeCl2
Half reactions,
Fe3++eFe2+;Reduction;E=0.76 volt
Sn2+Sn4++2e;Oxidation;E=0.15 volt––––––––––––––––––––––––––––
Adding;emf=+0.61 volt
Since, emf is positive, the reaction will occur.

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