(a) Chemical reaction,
Fe3++Ce3+→Ce4++Fe2+
Two half reactions,
Fe3++e→Fe2+;Reduction;E∘=0.76 volt
Ce3+→Ce4++e−;Oxidation;E∘OX=−1.60 volt––––––––––––––––––––––––––––––––
Adding;emf=−0.84 volt
Since, emf is negative, the reaction does not occur, i.e., Fe3+ does not oxidise Ce3+.
(b) Chemical reaction,
I2+2KCl=2KI=Cl2
Half reactions,
I2+2e−→2I−;Reduction;E∘=0.53 volt
2Cl−→Cl2+2e−;underlineOxidation;E∘OX=−1.36 volt
Adding;emf=−0.82 volt
Since, emf is negative, the reaction does not occur, i.e., I2 does not displace Cl2 from KCl.
(c) Chemical reaction,
SnCl2+2FeCl3→SnCl4+2FeCl2
Half reactions,
Fe3++e−→Fe2+;Reduction;E∘=0.76 volt
Sn2+→Sn4++2e−;Oxidation;E∘=−0.15 volt––––––––––––––––––––––––––––––
Adding;emf=+0.61 volt
Since, emf is positive, the reaction will occur.