The values of four quantum numbers of valence electron of an element $X$ is $n = 4, l = 0, m = 0, s = 1 / 2$ . The element is:

K

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T i

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N a

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S c

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Solution

The correct option is D $K$
$n = 4$
$l = 0$
$m = 0$
$s = \frac{1}{2}$
$\Rightarrow$ $s -$ orbital.
$S^{'}$ is valance orbital of ( $K$ ) potassium.

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