The values of four quantum numbers of valence electrons in an element X are n = 4, l = 0, m = 0, $s = \frac{1}{2}$ . The element is:

K

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T i

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N a

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S c

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Solution

The correct option is A $K$
The valence electron is in the 4s orbital since $n = 4, l = 0, m = 0, s = \frac{1}{2}$ . Therefore, possible elements are K and Ca.

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