Question

the values of l,C and R for a circuit are 1 H, 9 F, and $3\Omega$. what is the quality factor for the circuit at resonance ?

• A. 1
• B. 9
• C. 19
• D. 13

Answer 1

The correct option is A 1

Given : $R=3\Omega$ $L=1H$ $C=9F$

Quality factor $Q=\frac{1}{R}\sqrt{\frac{L}{C}}$

So, $Q=\frac{1}{3}\sqrt{\frac{1}{9}}=1$