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Question

The values of the expression sin3y1+cosy+cos3y1siny are :

A
2sin(π4+y)
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B
2cos(π4y)
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C
2sin(π4y)
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D
2cos(π4+y).
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Solution

The correct options are
A 2sin(π4+y)
C 2cos(π4y)

sin3y1+cosy+cos3y1siny
sin3y(1cosy)1cos2y+cos3y(1+siny)1sin2y
siny(1cosy)+cosy(1+siny)siny+cosy
sin(π4+y) or 2cos(π4y)


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