The van ’t Hoff factor of $H g_{2} C l_{2}$ in its aqueous solution will be $(H g_{2} C l_{2}$ is 80% ionized in the solution):

1.6

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2.6

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3.6

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4.6

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Solution

The correct option is B 2.6
$H g_{2} C l_{2} ⇌ H g_{2}^{2 +} + 2 C l^{-}$
n = 3
$α$ = $\frac{i - 1}{n - 1}$
$0.8$ = $\frac{i - 1}{3 - 1}$
i = 2.6

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Q. The van ’t Hoff factor of

H g_{2} C l_{2}

in its aqueous solution will be

(H g_{2} C l_{2}

is 80% ionized in the solution):

Q. Van’t Hoff factor of

H g_{2} C l_{2}

in its aqueous solution will be

(H g_{2} C l_{2}

is 80% ionized is the solution)

Q. If

H g_{2} C l_{2}

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(i) Mole fraction

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The van ’t Hoff factor of Hg2Cl2 in its aqueous solution will be (Hg2Cl2 is 80% ionized in the solution):

The correct option is B 2.6Hg2Cl2⇌ Hg2+2 + 2Cl− n = 3 α = i−1n−1 0.8 = i−13−1 i = 2.6

The van ’t Hoff factor of $H g_{2} C l_{2}$ in its aqueous solution will be $(H g_{2} C l_{2}$ is 80% ionized in the solution):

The correct option is B 2.6
$H g_{2} C l_{2} ⇌ H g_{2}^{2 +} + 2 C l^{-}$
n = 3
$α$ = $\frac{i - 1}{n - 1}$
$0.8$ = $\frac{i - 1}{3 - 1}$
i = 2.6